Physics 7 (Winter 08) – Homework #6
Due:2/19
- In a
forest in Brazil a tree
falls just as a guru in India
levitates. The fallen tree blocks a stream that causes a small swamp to
form while the guru comes down to earth and proceeds to drink a (very
large) cup of tea. In what sequence
would these events be seen by an observer moving at very high speed?
- Imagine
that we place a large number of negative charges in a straight line. An
observer is moving at constant speed in a direction parallel to the lie of
charges, then
- The
observer will measure neither electric nor magnetic effects
- In
the observer’s frame of reference the charges are moving and he will see
a magnetic field since moving charges generate magnetic effects
- In
the observer’s reference frame the charges are moving but there will be
no magnetic effects
- The
observer will see that the charges change sign or not depending on his
direction of motion
- The
observer will see precisely the same electric and magnetic effects as
when at rest with respect to the charges
- John
is in a spaceship and watches Mary in another spaceship moving at a very
large speed with respect to him. Then
- John
sees Mary aging faster than he does and Mary sees herself aging faster
than John does
- John
sees Mary aging slower than he does and Mary sees herself aging slower
than John does
- John
sees Mary aging slower than he does and Mary sees herself aging faster
than John does
- John
sees Mary aging faster than he does and Mary sees herself aging slower
than John does
- John
and Mary see each other aging at the same rate
- A
plastic rocket is precisely 1 m long; in it there is a steel rod that just
fits inside the rocket lengthwise. When the rocket travels at a constant
speed close to c in outer space,
- The
metal rod suffers length contraction but to a lesser degree than the
rocket because steel is more rigid than plastic, so that the rod will pierce
the rocket
- The
metal rod does not suffer length contraction at all but the rocket does,
so that the rod will pierce the rocket
- Both
the rocket at the rod suffer length contraction, but the effect is larger
on the rod which will then float loosely inside the rocket
- The
rod will be “pushed” towards the back of the rocket since it is traveling
at constant speed
- Both
rod and rocket suffer precisely the same degree of length contraction so
that the rod will continue to just fit inside.
- In
the news today: a meteorite entered the atmosphere and hit Mr. A. Arnold
breaking his leg. Mr. O, an observer moving very fast with respect to the
Earth, will find that
- Mr.
A’s leg breaks before the meteorite enters the atmosphere
- Mr.
A’s leg breaks before or after the meteorite enters the atmosphere,
depending on the direction of motion of Mr. O.
- That
Mr. A’s leg breaks after the meteorite enters the atmosphere, no matter
how fast or in what direction Mr. O is traveling
- Mr.
A’s leg breaks just as the meteorite enters the atmosphere
- Mr.
A’s leg breaks before or at the same time as the meteorite enters the
atmosphere, depending on the direction of motion of Mr. O.
- If
Fred weighs precisely 80kg when he is moving with respect to the scale then,
when he is at rest with respect to the scales, he will
- Still
weigh precisely 80kg
- Always
weigh slightly less than 80 kg
- Always
weigh slightly more than 80kg
- Weigh
slightly less than 80 kg only if he was moving at speed c
- Weigh
slightly more or less than 80 kg depending on whether he was moving
eastward or westward.
- Nuclear
weapons and reactors work by
- Burning
coal
- Using
reactions where a small amount of subatomic mass is converted into energy
- Using
reaction where a bit of energy is converted into mass
- Accelerating
atomic nuclei until they reach speeds close to c
- Slowing
atomic nuclei that naturally move at speeds close to c
- Subatomic
particles are often unstable and decay after a short time, which means
they spontaneously break apart after that time. Imagine that Alfred in his
laboratory here on Earth measures that, at rest, one type of subatomic
particle takes 1 second to decay. Imagine also that Winifred (in her
laboratory, also on Earth) finds that the decay of the same type of
particle takes it 2 seconds when it is moving at a very fast speed. Then
- One
must discard Winifred’s results because time of decay cannot be measured accurately
for moving particles
- One
must discard Alfred’s results because his particle was not really at rest
since the Earth is rotating
- Both
can be right since the particle behaves as a clock and moving clocks slow down
- If
correct, this result would contradict the special theory of relativity
which predicts that a moving particle would decay in a shorter time than when at rest
- One
of the measurements must be wrong, but one can only find out which by
doing experiments in outer space.
- A
rocket which is precisely 100 m long goes through a spherical asteroid
which has a diameter also of 100 m (and a hole for the rocket to go thorough).
According to an observer on the asteroid the rocket is length-contracted
and so will fit inside asteroid for a short time; according to the
astronaut in the rocket the asteroid is length-contracted so the rocket
will not fit inside the asteroid at any time. Who is right?
- Both:
whether the rocket fits or not inside is a statement that depend on the
frame of reference
- The
observer on the asteroid
- The
astronaut
- Neither
- When
Superman runs very fast with respect to us he looks
- Shorter
and stouter than when at rest
- Shorter
and thinner than when at rest
- Taller
and stouter than when at rest
- The
same height as when at rest but thinner
- The
same height as when at rest but stouter